What is the answer to solvefor n,n+(n-2)+(n-4)+(n-6)=-72 ?

The answer to solvefor n,n+(n-2)+(n-4)+(n-6)=-72 is n=-15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

Solve for n n+(n-2)+(n-4)+(n-6)=-72

solve for

n, n + (n - 2) + (n - 4) + (n - 6) = - 72

n = - 15

Solution steps

n + (n - 2) + (n - 4) + (n - 6) = - 72

Remove parentheses:

(a) = a

n + n - 2 + n - 4 + n - 6 = - 72

Group like terms

n + n + n + n - 2 - 4 - 6 = - 72

Add similar elements:

n + n + n + n = 4 n

4 n - 2 - 4 - 6 = - 72

Subtract the numbers:

- 2 - 4 - 6 = - 12

4 n - 12 = - 72

Move

12

to the right side

4 n = - 60

Divide both sides by

4

n = - 15

6^{\frac{2}{3}}

x, 8 x - 11 = 3 x - 13

y, 6 = 2 (y + 2)

4 x^{3} + x^{2} - 8 x - 2

x, 3 x^{2} + 5 x = 2

What is the answer to solvefor n,n+(n-2)+(n-4)+(n-6)=-72 ?
The answer to solvefor n,n+(n-2)+(n-4)+(n-6)=-72 is n=-15