What are the solutions to the equation roots 3x^2+26x-9 ?

The solutions to the equation roots 3x^2+26x-9 are x= 1/3 ,x=-9

Find the zeros of roots 3x^2+26x-9

The zeros of roots 3x^2+26x-9 are x= 1/3 ,x=-9

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roots

3 x^{2} + 26 x - 9

x = \frac{1}{3}, x = - 9

Solution steps

3 x^{2} + 26 x - 9

The roots are the intercepts with the x-axis

(y = 0)

3 x^{2} + 26 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

2 6^{2} - 4 \cdot 3 (- 9) = 28

x_{1, 2} = \frac{- 26 \pm 28}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 26 + 28}{2 \cdot 3}, x_{2} = \frac{- 26 - 28}{2 \cdot 3}

x = \frac{- 26 + 28}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 26 - 28}{2 \cdot 3} : - 9

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 9

\frac{4}{( 3 )}

42%

x, 1 6^{x} = 8

(- 7) (- 6)

x, \frac{( 9 - x )}{5} = 3

What are the solutions to the equation roots 3x^2+26x-9 ?
The solutions to the equation roots 3x^2+26x-9 are x= 1/3 ,x=-9
Find the zeros of roots 3x^2+26x-9
The zeros of roots 3x^2+26x-9 are x= 1/3 ,x=-9