What are the solutions to the equation quadraticformula 3x^2-2x-4=0 ?

The solutions to the equation quadraticformula 3x^2-2x-4=0 are x=(1+sqrt(13))/3 ,x=(1-sqrt(13))/3

Find the zeros of quadraticformula 3x^2-2x-4=0

The zeros of quadraticformula 3x^2-2x-4=0 are x=(1+sqrt(13))/3 ,x=(1-sqrt(13))/3

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3 x^{2} - 2 x - 4 = 0

x = \frac{1 + 13}{3}, x = \frac{1 - 13}{3}

Decimal Notation

x = 1.53518 \dots, x = - 0.86851 \dots

Solution steps

3 x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 4) = 213

x_{1, 2} = \frac{- ( - 2 ) \pm 2 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 13}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 13}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 13}{2 \cdot 3} : \frac{1 + 13}{3}

x = \frac{- ( - 2 ) - 2 13}{2 \cdot 3} : \frac{1 - 13}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 13}{3}, x = \frac{1 - 13}{3}

15 x - 3

s, \frac{s}{( 2 s + 6 )} - \frac{2}{( 5 s + 5 )} = \frac{( 5 s ^{2} - 3 s - 7 )}{( 10 s ^{2} + 40 s + 30 )}

x, 2^{- x} = 1.5

157

(\frac{- 4}{3})^{3}

What are the solutions to the equation quadraticformula 3x^2-2x-4=0 ?
The solutions to the equation quadraticformula 3x^2-2x-4=0 are x=(1+sqrt(13))/3 ,x=(1-sqrt(13))/3
Find the zeros of quadraticformula 3x^2-2x-4=0
The zeros of quadraticformula 3x^2-2x-4=0 are x=(1+sqrt(13))/3 ,x=(1-sqrt(13))/3