What is the answer to solvefor n,(0.03)/(500)*(9000)=(1+0.03)^n-1 ?

The answer to solvefor n,(0.03)/(500)*(9000)=(1+0.03)^n-1 is n=(ln(77/50))/(ln(1.03))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

Solve for n 0.03/500*(9000)=(1+0.03)^n-1

solve for

n, \frac{0.03}{500} \cdot (9000) = (1 + 0.03)^{n} - 1

n = \frac{ln ( \frac{77}{50} )}{ln ( 1.03 )}

Decimal

n = 14.60757 \dots

Solution steps

\frac{0.03}{500} (9000) = (1 + 0.03)^{n} - 1

Switch sides

(1 + 0.03)^{n} - 1 = \frac{0.03}{500} \cdot 9000

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

(1 + 0.03)^{n} - 1 = \frac{0.03 \cdot 9000}{500}

Multiply the numbers:

0.03 \cdot 9000 = 270

(1 + 0.03)^{n} - 1 = \frac{270}{500}

Cancel the common factor:

10

(1 + 0.03)^{n} - 1 = \frac{27}{50}

Move

1

to the right side

(1 + 0.03)^{n} = \frac{77}{50}

Apply exponent rules

n ln (1 + 0.03) = ln (\frac{77}{50})

Solve

n ln (1 + 0.03) = ln (\frac{77}{50}) : n = \frac{ln ( \frac{77}{50} )}{ln ( 1.03 )}

n = \frac{ln ( \frac{77}{50} )}{ln ( 1.03 )}

- 3.6 (3)

x^{2} - 5 x - 24 = 0

\frac{( 30 ! )}{( 26 ! )}

(r - s) (x - 4)

x^{2} + 17 x + 70 = 0

What is the answer to solvefor n,(0.03)/(500)*(9000)=(1+0.03)^n-1 ?
The answer to solvefor n,(0.03)/(500)*(9000)=(1+0.03)^n-1 is n=(ln(77/50))/(ln(1.03))