What is y=mx+b,x+4y=28 ?

The solution to y=mx+b,x+4y=28 is

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Write in y=mx+b Form x+4y=28

y = m x + b, x + 4 y = 28

(x = \frac{28 - 4 b}{1 + 4 m}, y = \frac{m ( 28 - 4 b )}{1 + 4 m} + b)

Solution steps

[y = m x + b x + 4 y = 28]

Isolate

y

for

y = m x + b : y = m x + b

Plug the solutions

y = m x + b

into

x + 4 y = 28

For

x + 4 y = 28

, subsitute

y

with

m x + b : x = \frac{28 - 4 b}{1 + 4 m}; m \neq = - \frac{1}{4}

Plug the solutions

x = \frac{28 - 4 b}{1 + 4 m}

into

y = m x + b

For

y = m x + b

, subsitute

x

with

\frac{28 - 4 b}{1 + 4 m} : y = \frac{m ( 28 - 4 b )}{1 + 4 m} + b

Verify solutions by plugging them into the original equations

Therefore, the final solution for

y = m x + b, x + 4 y = 28

(x = \frac{28 - 4 b}{1 + 4 m}, y = \frac{m ( 28 - 4 b )}{1 + 4 m} + b)

r, 20 r = - 5 (13 r - 17)

\frac{125}{2}

2.5

x, 2 x + 5 = 10

2.1%