What are the solutions to the equation quadraticformula x^2-3x=10 ?

The solutions to the equation quadraticformula x^2-3x=10 are x=5,x=-2

Find the zeros of quadraticformula x^2-3x=10

The zeros of quadraticformula x^2-3x=10 are x=5,x=-2

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x^{2} - 3 x = 10

x = 5, x = - 2

Solution steps

x^{2} - 3 x = 10

Move

10

to the left side

x^{2} - 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

x = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

x = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 5, x = - 2

\frac{5 x}{12}

(- 6.6)^{2}

\frac{7}{16} - \frac{7}{20}

x, ∣ x - 2 ∣ = 6

z, 42 = - 7 (z - 3)

What are the solutions to the equation quadraticformula x^2-3x=10 ?
The solutions to the equation quadraticformula x^2-3x=10 are x=5,x=-2
Find the zeros of quadraticformula x^2-3x=10
The zeros of quadraticformula x^2-3x=10 are x=5,x=-2