What are the solutions to the equation quadraticformula x^2=18x-81 ?

The solutions to the equation quadraticformula x^2=18x-81 are x=9

Find the zeros of quadraticformula x^2=18x-81

The zeros of quadraticformula x^2=18x-81 are x=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} = 18 x - 81

x = 9

Solution steps

x^{2} = 18 x - 81

Move

81

to the left side

x^{2} + 81 = 18 x

Move

18 x

to the left side

x^{2} + 81 - 18 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 18 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 81 = 0

x_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 18 )}{2 \cdot 1}

\frac{- ( - 18 )}{2 \cdot 1} = 9

x = 9

The solution to the quadratic equation is:

x = 9

p, 4 + 2 p = 10 (\frac{3}{5 p - 2})

100 x^{2}

x^{2} + 13 x + 36 = 0

t, 16 - 2 t = t + 9 + 4 t

120/60

What are the solutions to the equation quadraticformula x^2=18x-81 ?
The solutions to the equation quadraticformula x^2=18x-81 are x=9
Find the zeros of quadraticformula x^2=18x-81
The zeros of quadraticformula x^2=18x-81 are x=9