What is simplify ((9x^2-4))/((3x^2-5x+2))*((9x^4-6x^3+4x^2))/((27x^4+8x)) ?

The solution to simplify ((9x^2-4))/((3x^2-5x+2))*((9x^4-6x^3+4x^2))/((27x^4+8x)) is x/(x-1)

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Simplify (9x^2-4)/(3x^2-5x+2)*(9x^4-6x^3+4x^2)/(27x^4+8x)

simplify

\frac{( 9 x ^{2} - 4 )}{( 3 x ^{2} - 5 x + 2 )} \cdot \frac{( 9 x ^{4} - 6 x ^{3} + 4 x ^{2} )}{( 27 x ^{4} + 8 x )}

\frac{x}{x - 1}

Solution steps

\frac{9 x ^{2} - 4}{3 x ^{2} - 5 x + 2} \cdot \frac{9 x ^{4} - 6 x ^{3} + 4 x ^{2}}{27 x ^{4} + 8 x}

Cancel

\frac{9 x ^{2} - 4}{3 x ^{2} - 5 x + 2} : \frac{3 x + 2}{x - 1}

= \frac{3 x + 2}{x - 1} \cdot \frac{9 x ^{4} - 6 x ^{3} + 4 x ^{2}}{27 x ^{4} + 8 x}

Cancel

\frac{9 x ^{4} - 6 x ^{3} + 4 x ^{2}}{27 x ^{4} + 8 x} : \frac{x}{3 x + 2}

= \frac{3 x + 2}{x - 1} \cdot \frac{x}{3 x + 2}

Cross-cancel common factor:

3 x + 2

= \frac{x}{x - 1}

67

\frac{3}{( 2 )}

\frac{69}{18}

\frac{225}{9}

x, 2 x - 3 = 3 x - 5

What is simplify ((9x^2-4))/((3x^2-5x+2))*((9x^4-6x^3+4x^2))/((27x^4+8x)) ?
The solution to simplify ((9x^2-4))/((3x^2-5x+2))*((9x^4-6x^3+4x^2))/((27x^4+8x)) is x/(x-1)