What are the solutions to the equation 2(x+3)^2=24 ?

The solutions to the equation 2(x+3)^2=24 are x=2sqrt(3)-3,x=-2sqrt(3)-3

Find the zeros of 2(x+3)^2=24

The zeros of 2(x+3)^2=24 are x=2sqrt(3)-3,x=-2sqrt(3)-3

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2 (x + 3)^{2} = 24

x = 23 - 3, x = - 23 - 3

Solution steps

2 (x + 3)^{2} = 24

Divide both sides by

2

(x + 3)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 12 : x = 23 - 3

Solve

x + 3 = - 12 : x = - 23 - 3

The solutions to the quadratic equation are:

x = 23 - 3, x = - 23 - 3

3 (x - 4) = 4 - 2 (x + 2)

(x - 6)^{2} + x^{2} - 6 x - 2 = 0

\frac{( 2 + 4 - 3 ) ^{2} - 1}{- 4}

x^{2} - 147 = 0

(\frac{1}{16})^{\frac{5}{4}}

What are the solutions to the equation 2(x+3)^2=24 ?
The solutions to the equation 2(x+3)^2=24 are x=2sqrt(3)-3,x=-2sqrt(3)-3
Find the zeros of 2(x+3)^2=24
The zeros of 2(x+3)^2=24 are x=2sqrt(3)-3,x=-2sqrt(3)-3