What are the solutions to the equation quadraticformula-6x-1+5x^2=8x^2 ?

The solutions to the equation quadraticformula-6x-1+5x^2=8x^2 are x=-(3+sqrt(6))/3 ,x=-(3-sqrt(6))/3

Find the zeros of quadraticformula-6x-1+5x^2=8x^2

The zeros of quadraticformula-6x-1+5x^2=8x^2 are x=-(3+sqrt(6))/3 ,x=-(3-sqrt(6))/3

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- 6 x - 1 + 5 x^{2} = 8 x^{2}

x = - \frac{3 + 6}{3}, x = - \frac{3 - 6}{3}

Decimal Notation

x = - 1.81649 \dots, x = - 0.18350 \dots

Solution steps

- 6 x - 1 + 5 x^{2} = 8 x^{2}

Move

8 x^{2}

to the left side

- 6 x - 1 - 3 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} - 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 3 ) ( - 1 )}{2 ( - 3 )}

(- 6)^{2} - 4 (- 3) (- 1) = 26

x_{1, 2} = \frac{- ( - 6 ) \pm 2 6}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 6}{2 ( - 3 )}, x_{2} = \frac{- ( - 6 ) - 2 6}{2 ( - 3 )}

x = \frac{- ( - 6 ) + 2 6}{2 ( - 3 )} : - \frac{3 + 6}{3}

x = \frac{- ( - 6 ) - 2 6}{2 ( - 3 )} : - \frac{3 - 6}{3}

The solutions to the quadratic equation are:

x = - \frac{3 + 6}{3}, x = - \frac{3 - 6}{3}

x, - 4 \leq - 4 x - 12 < 4

y, \frac{0.5}{9} = \frac{y}{30}

x, 2 x = 12

x^{2} = 2 x - 5

(- 1)^{1.5}

What are the solutions to the equation quadraticformula-6x-1+5x^2=8x^2 ?
The solutions to the equation quadraticformula-6x-1+5x^2=8x^2 are x=-(3+sqrt(6))/3 ,x=-(3-sqrt(6))/3
Find the zeros of quadraticformula-6x-1+5x^2=8x^2
The zeros of quadraticformula-6x-1+5x^2=8x^2 are x=-(3+sqrt(6))/3 ,x=-(3-sqrt(6))/3