What are the solutions to the equation 2x^2+3x+6=4x ?

The solutions to the equation 2x^2+3x+6=4x are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4

Find the zeros of 2x^2+3x+6=4x

The zeros of 2x^2+3x+6=4x are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4

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2 x^{2} + 3 x + 6 = 4 x

x = \frac{1}{4} + i \frac{47}{4}, x = \frac{1}{4} - i \frac{47}{4}

Solution steps

2 x^{2} + 3 x + 6 = 4 x

Move

4 x

to the left side

2 x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

(- 1)^{2} - 4 \cdot 2 \cdot 6 : 47 i

x_{1, 2} = \frac{- ( - 1 ) \pm 47 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 47 i}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 47 i}{2 \cdot 2}

x = \frac{- ( - 1 ) + 47 i}{2 \cdot 2} : \frac{1}{4} + i \frac{47}{4}

x = \frac{- ( - 1 ) - 47 i}{2 \cdot 2} : \frac{1}{4} - i \frac{47}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{47}{4}, x = \frac{1}{4} - i \frac{47}{4}

3 x^{2} - 10 x = 8

10 - 8 \frac{7}{8}

j, 6 j - 11 j - 11 j + 19 = - 13

4.75%

66 \frac{2}{3} %

What are the solutions to the equation 2x^2+3x+6=4x ?
The solutions to the equation 2x^2+3x+6=4x are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4
Find the zeros of 2x^2+3x+6=4x
The zeros of 2x^2+3x+6=4x are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4