What are the solutions to the equation quadraticformula 2x^2-3x=5 ?

The solutions to the equation quadraticformula 2x^2-3x=5 are x= 5/2 ,x=-1

Find the zeros of quadraticformula 2x^2-3x=5

The zeros of quadraticformula 2x^2-3x=5 are x= 5/2 ,x=-1

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2 x^{2} - 3 x = 5

x = \frac{5}{2}, x = - 1

Decimal Notation

x = 2.5, x = - 1

Solution steps

2 x^{2} - 3 x = 5

Move

5

to the left side

2 x^{2} - 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 5) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 2}

x = \frac{- ( - 3 ) + 7}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 3 ) - 7}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - 1

x, \frac{2}{7} = \frac{x}{21}

x, 2 (2 x - 4) = 4 (x - 2)

q, 17 q - 6 q + q - 9 q = 15

7 x^{- 4}

x + 3 y + 6 z = 19, 2 x - 3 y + 3 z = 2

What are the solutions to the equation quadraticformula 2x^2-3x=5 ?
The solutions to the equation quadraticformula 2x^2-3x=5 are x= 5/2 ,x=-1
Find the zeros of quadraticformula 2x^2-3x=5
The zeros of quadraticformula 2x^2-3x=5 are x= 5/2 ,x=-1