What are the solutions to the equation quadraticformula x^2-5x-36=0 ?

The solutions to the equation quadraticformula x^2-5x-36=0 are x=9,x=-4

Find the zeros of quadraticformula x^2-5x-36=0

The zeros of quadraticformula x^2-5x-36=0 are x=9,x=-4

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x^{2} - 5 x - 36 = 0

x = 9, x = - 4

Solution steps

x^{2} - 5 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 36) = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 1}

x = \frac{- ( - 5 ) + 13}{2 \cdot 1} : 9

x = \frac{- ( - 5 ) - 13}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 9, x = - 4

(\frac{- 27}{64})^{\frac{- 1}{3}}

x, ∣ 2 x - 3 ∣ = - 1

14/5 \frac{5}{6}

x, ∣ x + 3 ∣ = 10

72 x^{2} - 2

What are the solutions to the equation quadraticformula x^2-5x-36=0 ?
The solutions to the equation quadraticformula x^2-5x-36=0 are x=9,x=-4
Find the zeros of quadraticformula x^2-5x-36=0
The zeros of quadraticformula x^2-5x-36=0 are x=9,x=-4