What are the solutions to the equation factor x^2-13x+42=0 ?

The solutions to the equation factor x^2-13x+42=0 are x=6,x=7

Find the zeros of factor x^2-13x+42=0

The zeros of factor x^2-13x+42=0 are x=6,x=7

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x^{2} - 13 x + 42 = 0

x = 6, x = 7

Solution steps

x^{2} - 13 x + 42 = 0

Factor

x^{2} - 13 x + 42 : (x - 6) (x - 7)

(x - 6) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x - 7 = 0

Solve

x - 6 = 0 : x = 6

Solve

x - 7 = 0 : x = 7

The solutions to the quadratic equation are:

x = 6, x = 7

y, y - \frac{3}{4} = \frac{5}{6}

\frac{64}{81}

1 \frac{1}{2} \cdot 1 \frac{1}{2}

(x - 9) (x - 6)

k, 5 = \frac{k}{8}

What are the solutions to the equation factor x^2-13x+42=0 ?
The solutions to the equation factor x^2-13x+42=0 are x=6,x=7
Find the zeros of factor x^2-13x+42=0
The zeros of factor x^2-13x+42=0 are x=6,x=7