因式分解 x^2-13x+42=0

解答

x^{2} - 13 x + 42 = 0

x = 6, x = 7

求解步骤

x^{2} - 13 x + 42 = 0

因式分解

x^{2} - 13 x + 42 : (x - 6) (x - 7)

(x - 6) (x - 7) = 0

使用零因数法则： If

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x - 7 = 0

解

x - 6 = 0 : x = 6

解

x - 7 = 0 : x = 7

二次方程组的解是:

x = 6, x = 7

y, y - \frac{3}{4} = \frac{5}{6}

\frac{64}{81}

1 \frac{1}{2} \cdot 1 \frac{1}{2}

(x - 9) (x - 6)

k, 5 = \frac{k}{8}