What is the answer to solvefor h,s=2pirh+2pir^2 ?

The answer to solvefor h,s=2pirh+2pir^2 is h=-r-(is)/(2pr);\quad 2pir\ne 0

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Solve for h s=2pirh+2pir^2

solve for

h, s = 2 p i r h + 2 p i r^{2}

h = - r - \frac{i s}{2 p r}; 2 p i r \neq = 0

Solution steps

s = 2 p i r h + 2 p i r^{2}

Switch sides

2 p i r h + 2 p i r^{2} = s

Move

2 p i r^{2}

to the right side

2 p i r h = s - 2 p i r^{2}

Divide both sides by

2 p i r; 2 p i r \neq = 0

h = - r - i \frac{s}{2 p r}; 2 p i r \neq = 0

Simplify

- r - i \frac{s}{2 p r} : - r - \frac{i s}{2 p r}

h = - r - \frac{i s}{2 p r}; 2 p i r \neq = 0

\frac{60}{54}

p, p - 18 = 3

x, ∣ x ∣ = 17

\frac{25}{( 10 )}

18.5 \cdot 25%

What is the answer to solvefor h,s=2pirh+2pir^2 ?
The answer to solvefor h,s=2pirh+2pir^2 is h=-r-(is)/(2pr);\quad 2pir\ne 0