What are the solutions to the equation quadraticformula x^2-10x=-13 ?

The solutions to the equation quadraticformula x^2-10x=-13 are x=5+2sqrt(3),x=5-2sqrt(3)

Find the zeros of quadraticformula x^2-10x=-13

The zeros of quadraticformula x^2-10x=-13 are x=5+2sqrt(3),x=5-2sqrt(3)

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x^{2} - 10 x = - 13

x = 5 + 23, x = 5 - 23

Decimal Notation

x = 8.46410 \dots, x = 1.53589 \dots

Solution steps

x^{2} - 10 x = - 13

Move

13

to the left side

x^{2} - 10 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 13 = 43

x_{1, 2} = \frac{- ( - 10 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4 3}{2 \cdot 1} : 5 + 23

x = \frac{- ( - 10 ) - 4 3}{2 \cdot 1} : 5 - 23

The solutions to the quadratic equation are:

x = 5 + 23, x = 5 - 23

\frac{( 18 ! )}{( 10 ! )}

x, - 4 x = 100

x, 3 (2 x + 5) = 39

9^{- 2} 0.5

x, 7 x - 2 > 5 x + 8

What are the solutions to the equation quadraticformula x^2-10x=-13 ?
The solutions to the equation quadraticformula x^2-10x=-13 are x=5+2sqrt(3),x=5-2sqrt(3)
Find the zeros of quadraticformula x^2-10x=-13
The zeros of quadraticformula x^2-10x=-13 are x=5+2sqrt(3),x=5-2sqrt(3)