What are the solutions to the equation quadraticformula x^2=9x-14 ?

The solutions to the equation quadraticformula x^2=9x-14 are x=7,x=2

Find the zeros of quadraticformula x^2=9x-14

The zeros of quadraticformula x^2=9x-14 are x=7,x=2

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x^{2} = 9 x - 14

x = 7, x = 2

Solution steps

x^{2} = 9 x - 14

Move

14

to the left side

x^{2} + 14 = 9 x

Move

9 x

to the left side

x^{2} + 14 - 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 9 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 14 = 5

x_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 1}

x = \frac{- ( - 9 ) + 5}{2 \cdot 1} : 7

x = \frac{- ( - 9 ) - 5}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 7, x = 2

x, 2^{x} = 18

3 - (4 x - 5) + 6

- 13

7^{- 1} 0.5

- \frac{5}{18}

What are the solutions to the equation quadraticformula x^2=9x-14 ?
The solutions to the equation quadraticformula x^2=9x-14 are x=7,x=2
Find the zeros of quadraticformula x^2=9x-14
The zeros of quadraticformula x^2=9x-14 are x=7,x=2