What are the solutions to the equation quadraticformula x(x-8)=0 ?

The solutions to the equation quadraticformula x(x-8)=0 are x=8,x=0

Find the zeros of quadraticformula x(x-8)=0

The zeros of quadraticformula x(x-8)=0 are x=8,x=0

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x (x - 8) = 0

x = 8, x = 0

Solution steps

x (x - 8) = 0

Expand

x (x - 8) : x^{2} - 8 x

x^{2} - 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

x_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

x = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 8, x = 0

x, 25 6^{x} = 64

x, 2 x = x^{2}

R, R = \frac{( \frac{200}{3} )}{1.5} \cdot \frac{12000}{3}

r, - 10 - 5 r + 7 r = 10 - 8 (- 4 r - 5)

(\frac{- 14}{36}) (\frac{- ( 6 s )}{112})

What are the solutions to the equation quadraticformula x(x-8)=0 ?
The solutions to the equation quadraticformula x(x-8)=0 are x=8,x=0
Find the zeros of quadraticformula x(x-8)=0
The zeros of quadraticformula x(x-8)=0 are x=8,x=0