What are the solutions to the equation factor 6x^2+5x+1=0 ?

The solutions to the equation factor 6x^2+5x+1=0 are x=-1/3 ,x=-1/2

Find the zeros of factor 6x^2+5x+1=0

The zeros of factor 6x^2+5x+1=0 are x=-1/3 ,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 5 x + 1 = 0

x = - \frac{1}{3}, x = - \frac{1}{2}

Decimal Notation

x = - 0.33333 \dots, x = - 0.5

Solution steps

6 x^{2} + 5 x + 1 = 0

Factor

6 x^{2} + 5 x + 1 : (3 x + 1) (2 x + 1)

(3 x + 1) (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 1 = 0 or 2 x + 1 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - \frac{1}{2}

\frac{121}{100}

261

x, 2 x - 1 = 9

3 x - 2

x, 2 x + 4 = 12

What are the solutions to the equation factor 6x^2+5x+1=0 ?
The solutions to the equation factor 6x^2+5x+1=0 are x=-1/3 ,x=-1/2
Find the zeros of factor 6x^2+5x+1=0
The zeros of factor 6x^2+5x+1=0 are x=-1/3 ,x=-1/2