What are the solutions to the equation solvefor w,(4+w)(2w-1)=0 ?

The solutions to the equation solvefor w,(4+w)(2w-1)=0 are w=-4,w= 1/2

Find the zeros of solvefor w,(4+w)(2w-1)=0

The zeros of solvefor w,(4+w)(2w-1)=0 are w=-4,w= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

w, (4 + w) (2 w - 1) = 0

w = - 4, w = \frac{1}{2}

Solution steps

(4 + w) (2 w - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 + w = 0 or 2 w - 1 = 0

Solve

4 + w = 0 : w = - 4

Solve

2 w - 1 = 0 : w = \frac{1}{2}

The solutions to the quadratic equation are:

w = - 4, w = \frac{1}{2}

x, \frac{1}{x} - \frac{1}{3} = - \frac{1}{( 3 x )}

(f \cdot g) (4)

2 \frac{1}{4} \cdot 2 \frac{1}{2}

x, ∣ x ∣ \leq 7

x^{2} - 3 x - 9

What are the solutions to the equation solvefor w,(4+w)(2w-1)=0 ?
The solutions to the equation solvefor w,(4+w)(2w-1)=0 are w=-4,w= 1/2
Find the zeros of solvefor w,(4+w)(2w-1)=0
The zeros of solvefor w,(4+w)(2w-1)=0 are w=-4,w= 1/2