What are the solutions to the equation 3x^2-3x+12=0 ?

The solutions to the equation 3x^2-3x+12=0 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2

Find the zeros of 3x^2-3x+12=0

The zeros of 3x^2-3x+12=0 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2

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3 x^{2} - 3 x + 12 = 0

x = \frac{1}{2} + i \frac{15}{2}, x = \frac{1}{2} - i \frac{15}{2}

Solution steps

3 x^{2} - 3 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

Simplify

(- 3)^{2} - 4 \cdot 3 \cdot 12 : 315 i

x_{1, 2} = \frac{- ( - 3 ) \pm 3 15 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 15 i}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 3 15 i}{2 \cdot 3}

x = \frac{- ( - 3 ) + 3 15 i}{2 \cdot 3} : \frac{1}{2} + i \frac{15}{2}

x = \frac{- ( - 3 ) - 3 15 i}{2 \cdot 3} : \frac{1}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{15}{2}, x = \frac{1}{2} - i \frac{15}{2}

- - 11

3 x^{2} - 192

\frac{5}{n + 5} + \frac{4 n}{2 n + 6}

- 6

7 - (x + 2) = 1

What are the solutions to the equation 3x^2-3x+12=0 ?
The solutions to the equation 3x^2-3x+12=0 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2
Find the zeros of 3x^2-3x+12=0
The zeros of 3x^2-3x+12=0 are x= 1/2+i(sqrt(15))/2 ,x= 1/2-i(sqrt(15))/2