What are the solutions to the equation quadraticformula x^2=27 ?

The solutions to the equation quadraticformula x^2=27 are x=3sqrt(3),x=-3sqrt(3)

Find the zeros of quadraticformula x^2=27

The zeros of quadraticformula x^2=27 are x=3sqrt(3),x=-3sqrt(3)

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x^{2} = 27

x = 33, x = - 33

Solution steps

x^{2} = 27

Move

27

to the left side

x^{2} - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 27) = 63

x_{1, 2} = \frac{- 0 \pm 6 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 6 3}{2 \cdot 1}, x_{2} = \frac{- 0 - 6 3}{2 \cdot 1}

x = \frac{- 0 + 6 3}{2 \cdot 1} : 33

x = \frac{- 0 - 6 3}{2 \cdot 1} : - 33

The solutions to the quadratic equation are:

x = 33, x = - 33

144 x^{2} + 24 x + 1

x, 6 x - 4 = 0

\frac{5}{9 ( x - 32 )}

d, f = \frac{g + 6}{5 d}

24 x^{2}

What are the solutions to the equation quadraticformula x^2=27 ?
The solutions to the equation quadraticformula x^2=27 are x=3sqrt(3),x=-3sqrt(3)
Find the zeros of quadraticformula x^2=27
The zeros of quadraticformula x^2=27 are x=3sqrt(3),x=-3sqrt(3)