What are the solutions to the equation quadraticformula 5x^2-8x=3 ?

The solutions to the equation quadraticformula 5x^2-8x=3 are x=(4+sqrt(31))/5 ,x=(4-sqrt(31))/5

Find the zeros of quadraticformula 5x^2-8x=3

The zeros of quadraticformula 5x^2-8x=3 are x=(4+sqrt(31))/5 ,x=(4-sqrt(31))/5

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5 x^{2} - 8 x = 3

x = \frac{4 + 31}{5}, x = \frac{4 - 31}{5}

Solution steps

5 x^{2} - 8 x = 3

Move

3

to the left side

5 x^{2} - 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

(- 8)^{2} - 4 \cdot 5 (- 3) = 231

x_{1, 2} = \frac{- ( - 8 ) \pm 2 31}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 31}{2 \cdot 5}, x_{2} = \frac{- ( - 8 ) - 2 31}{2 \cdot 5}

x = \frac{- ( - 8 ) + 2 31}{2 \cdot 5} : \frac{4 + 31}{5}

x = \frac{- ( - 8 ) - 2 31}{2 \cdot 5} : \frac{4 - 31}{5}

The solutions to the quadratic equation are:

x = \frac{4 + 31}{5}, x = \frac{4 - 31}{5}

2 \frac{3}{12}

- 40 > 50

23.5%

n = 1 \sum 42 2 n - 2

D, D = \frac{( 40.5 g )}{( 15 m l )}

What are the solutions to the equation quadraticformula 5x^2-8x=3 ?
The solutions to the equation quadraticformula 5x^2-8x=3 are x=(4+sqrt(31))/5 ,x=(4-sqrt(31))/5
Find the zeros of quadraticformula 5x^2-8x=3
The zeros of quadraticformula 5x^2-8x=3 are x=(4+sqrt(31))/5 ,x=(4-sqrt(31))/5