What are the solutions to the equation quadraticformula x(x-1)=0 ?

The solutions to the equation quadraticformula x(x-1)=0 are x=1,x=0

Find the zeros of quadraticformula x(x-1)=0

The zeros of quadraticformula x(x-1)=0 are x=1,x=0

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x (x - 1) = 0

x = 1, x = 0

Solution steps

x (x - 1) = 0

Expand

x (x - 1) : x^{2} - x

x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

x = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

5 x^{2} - 32 x + 12

x, 8 x - 5 = 6 x + 3

x, 3^{x} = 30

z, - 20 < - 3 z - 2 < 10

\frac{7}{36}

What are the solutions to the equation quadraticformula x(x-1)=0 ?
The solutions to the equation quadraticformula x(x-1)=0 are x=1,x=0
Find the zeros of quadraticformula x(x-1)=0
The zeros of quadraticformula x(x-1)=0 are x=1,x=0