What are the solutions to the equation quadraticformula 5x^2+6x-6=0 ?

The solutions to the equation quadraticformula 5x^2+6x-6=0 are x=(-3+sqrt(39))/5 ,x=-(3+sqrt(39))/5

Find the zeros of quadraticformula 5x^2+6x-6=0

The zeros of quadraticformula 5x^2+6x-6=0 are x=(-3+sqrt(39))/5 ,x=-(3+sqrt(39))/5

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5 x^{2} + 6 x - 6 = 0

x = \frac{- 3 + 39}{5}, x = - \frac{3 + 39}{5}

Decimal Notation

x = 0.64899 \dots, x = - 1.84899 \dots

Solution steps

5 x^{2} + 6 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

6^{2} - 4 \cdot 5 (- 6) = 239

x_{1, 2} = \frac{- 6 \pm 2 39}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 2 39}{2 \cdot 5}, x_{2} = \frac{- 6 - 2 39}{2 \cdot 5}

x = \frac{- 6 + 2 39}{2 \cdot 5} : \frac{- 3 + 39}{5}

x = \frac{- 6 - 2 39}{2 \cdot 5} : - \frac{3 + 39}{5}

The solutions to the quadratic equation are:

x = \frac{- 3 + 39}{5}, x = - \frac{3 + 39}{5}

27 x^{6}

x, \frac{3}{2} x = - 6

x, 3 x + 7 = x - 1

x, 12 5^{x} = 5

\frac{36}{16}

What are the solutions to the equation quadraticformula 5x^2+6x-6=0 ?
The solutions to the equation quadraticformula 5x^2+6x-6=0 are x=(-3+sqrt(39))/5 ,x=-(3+sqrt(39))/5
Find the zeros of quadraticformula 5x^2+6x-6=0
The zeros of quadraticformula 5x^2+6x-6=0 are x=(-3+sqrt(39))/5 ,x=-(3+sqrt(39))/5