What are the solutions to the equation quadraticformula x^2-11x+24=0 ?

The solutions to the equation quadraticformula x^2-11x+24=0 are x=8,x=3

Find the zeros of quadraticformula x^2-11x+24=0

The zeros of quadraticformula x^2-11x+24=0 are x=8,x=3

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x^{2} - 11 x + 24 = 0

x = 8, x = 3

Solution steps

x^{2} - 11 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 24 = 5

x_{1, 2} = \frac{- ( - 11 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 5}{2 \cdot 1}

x = \frac{- ( - 11 ) + 5}{2 \cdot 1} : 8

x = \frac{- ( - 11 ) - 5}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 8, x = 3

- 22 - 34

29.53%

\frac{( 52 ! )}{( ( 52 - 4 ) ! \cdot 4 ! )}

\frac{( - 8 x ^{3} + 18 x ^{2} - 11 x + 21 )}{( - 2 x + 3 )}

2 x^{2} = 2 x - 3

What are the solutions to the equation quadraticformula x^2-11x+24=0 ?
The solutions to the equation quadraticformula x^2-11x+24=0 are x=8,x=3
Find the zeros of quadraticformula x^2-11x+24=0
The zeros of quadraticformula x^2-11x+24=0 are x=8,x=3