What are the solutions to the equation quadraticformula 3x^2-4x-2=0 ?

The solutions to the equation quadraticformula 3x^2-4x-2=0 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3

Find the zeros of quadraticformula 3x^2-4x-2=0

The zeros of quadraticformula 3x^2-4x-2=0 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3

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3 x^{2} - 4 x - 2 = 0

x = \frac{2 + 10}{3}, x = \frac{2 - 10}{3}

Solution steps

3 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 2) = 210

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 10}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 10}{2 \cdot 3} : \frac{2 + 10}{3}

x = \frac{- ( - 4 ) - 2 10}{2 \cdot 3} : \frac{2 - 10}{3}

The solutions to the quadratic equation are:

x = \frac{2 + 10}{3}, x = \frac{2 - 10}{3}

x, - 3 x + 6 = x - 10

x, ∣ 2 x - 1 ∣ = 8

v, \frac{( 5 v - 4 )}{10} = \frac{4}{5}

52%

\frac{24}{74}

What are the solutions to the equation quadraticformula 3x^2-4x-2=0 ?
The solutions to the equation quadraticformula 3x^2-4x-2=0 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3
Find the zeros of quadraticformula 3x^2-4x-2=0
The zeros of quadraticformula 3x^2-4x-2=0 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3