What is the answer to solvefor x,8^{-2x^2-10}=(1/64)^{-10x-16} ?

The answer to solvefor x,8^{-2x^2-10}=(1/64)^{-10x-16} is x=-7,x=-3

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Solve for x 8^(-2x^2-10)=(1/64)^(-10x-16)

solve for

x, 8^{- 2 x^{2} - 10} = (\frac{1}{64})^{- 10 x - 16}

x = - 7, x = - 3

Solution steps

8^{- 2 x^{2} - 10} = (\frac{1}{64})^{- 10 x - 16}

Apply exponent rules

- 2 x^{2} - 10 = - 2 (- 10 x - 16)

Solve

- 2 x^{2} - 10 = - 2 (- 10 x - 16) : x = - 7, x = - 3

x = - 7, x = - 3

7 n - (4 n - 3)

\frac{( 6 ! )}{( 4 ! \cdot 2 ! )}

\frac{1}{36}

\frac{120}{1000}

(2 x^{2} + 5 x - 7) + (3 - 4 x^{2} + 6 x)

What is the answer to solvefor x,8^{-2x^2-10}=(1/64)^{-10x-16} ?
The answer to solvefor x,8^{-2x^2-10}=(1/64)^{-10x-16} is x=-7,x=-3