What are the solutions to the equation 12x^2-25x+12=0 ?

The solutions to the equation 12x^2-25x+12=0 are x= 4/3 ,x= 3/4

Find the zeros of 12x^2-25x+12=0

The zeros of 12x^2-25x+12=0 are x= 4/3 ,x= 3/4

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12 x^{2} - 25 x + 12 = 0

x = \frac{4}{3}, x = \frac{3}{4}

Solution steps

12 x^{2} - 25 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 12 \cdot 12}{2 \cdot 12}

(- 25)^{2} - 4 \cdot 12 \cdot 12 = 7

x_{1, 2} = \frac{- ( - 25 ) \pm 7}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 7}{2 \cdot 12}, x_{2} = \frac{- ( - 25 ) - 7}{2 \cdot 12}

x = \frac{- ( - 25 ) + 7}{2 \cdot 12} : \frac{4}{3}

x = \frac{- ( - 25 ) - 7}{2 \cdot 12} : \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = \frac{3}{4}

\frac{5 x}{6} - \frac{x}{3} = \frac{1}{6}

x^{3} + 4 x^{2} - x \geq 4

18 x - 11 < 43

c^{2} + 6 c + 5

66

What are the solutions to the equation 12x^2-25x+12=0 ?
The solutions to the equation 12x^2-25x+12=0 are x= 4/3 ,x= 3/4
Find the zeros of 12x^2-25x+12=0
The zeros of 12x^2-25x+12=0 are x= 4/3 ,x= 3/4