What is solvefor x,x^2-x-2>0 ?

The solution to solvefor x,x^2-x-2>0 is x 2

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Solve for x x^2-x-2>0

solve for

x, x^{2} - x - 2 > 0

x < - 1 or x > 2

Solution steps

x^{2} - x - 2 > 0

Factor

x^{2} - x - 2 : (x + 1) (x - 2)

(x + 1) (x - 2) > 0

Identify the intervals

x < - 1 or x > 2

x, 8 x = 80

(0.25 x^{\frac{1}{4}})^{2} (12 x^{3})

3 x - 17 = - 2 x + 3

(- 9.5)^{2} (0.2 + 0.8)

\frac{- 81}{49}

What is solvefor x,x^2-x-2>0 ?
The solution to solvefor x,x^2-x-2>0 is x<-1\lor x>2