What are the solutions to the equation factor x^4-5x^2-36=0 ?

The solutions to the equation factor x^4-5x^2-36=0 are x=2i,x=-2i,x=-3,x=3

Find the zeros of factor x^4-5x^2-36=0

The zeros of factor x^4-5x^2-36=0 are x=2i,x=-2i,x=-3,x=3

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factor

x^{4} - 5 x^{2} - 36 = 0

x = 2 i, x = - 2 i, x = - 3, x = 3

Solution steps

x^{4} - 5 x^{2} - 36 = 0

Factor

x^{4} - 5 x^{2} - 36 : (x^{2} + 4) (x + 3) (x - 3)

(x^{2} + 4) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} + 4 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 2 i, x = - 2 i, x = - 3, x = 3

6 n^{4} - 24 n^{3} + 18 n

6.75%

140%

\frac{5}{25}

w, (3 - w) (4 w - 9) = 0

What are the solutions to the equation factor x^4-5x^2-36=0 ?
The solutions to the equation factor x^4-5x^2-36=0 are x=2i,x=-2i,x=-3,x=3
Find the zeros of factor x^4-5x^2-36=0
The zeros of factor x^4-5x^2-36=0 are x=2i,x=-2i,x=-3,x=3