What are the solutions to the equation -x^2+x=0 ?

The solutions to the equation -x^2+x=0 are x=0,x=1

Find the zeros of -x^2+x=0

The zeros of -x^2+x=0 are x=0,x=1

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- x^{2} + x = 0

x = 0, x = 1

Solution steps

- x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 1 )}, x_{2} = \frac{- 1 - 1}{2 ( - 1 )}

x = \frac{- 1 + 1}{2 ( - 1 )} : 0

x = \frac{- 1 - 1}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

- 9 \geq - 11 + v

- 3 \leq 2 x - 1 \leq 5

s^{2} - 17 s - 60

\frac{\frac{4}{5}}{2}

What are the solutions to the equation -x^2+x=0 ?
The solutions to the equation -x^2+x=0 are x=0,x=1
Find the zeros of -x^2+x=0
The zeros of -x^2+x=0 are x=0,x=1