What are the solutions to the equation quadraticformula x^2-12x+35=0 ?

The solutions to the equation quadraticformula x^2-12x+35=0 are x=7,x=5

Find the zeros of quadraticformula x^2-12x+35=0

The zeros of quadraticformula x^2-12x+35=0 are x=7,x=5

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x^{2} - 12 x + 35 = 0

x = 7, x = 5

Solution steps

x^{2} - 12 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 35 = 2

x_{1, 2} = \frac{- ( - 12 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2}{2 \cdot 1} : 7

x = \frac{- ( - 12 ) - 2}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 7, x = 5

(2 p^{2} + 7 q) (2 p^{2} - 7 q)

x, ∣ x - 5 ∣ = 1

5320

\frac{π - π}{10}

(- 20 x) (\frac{1}{4})

What are the solutions to the equation quadraticformula x^2-12x+35=0 ?
The solutions to the equation quadraticformula x^2-12x+35=0 are x=7,x=5
Find the zeros of quadraticformula x^2-12x+35=0
The zeros of quadraticformula x^2-12x+35=0 are x=7,x=5