What are the solutions to the equation solvefor f,(3f+2)(f-5)=0 ?

The solutions to the equation solvefor f,(3f+2)(f-5)=0 are f=-2/3 ,f=5

Find the zeros of solvefor f,(3f+2)(f-5)=0

The zeros of solvefor f,(3f+2)(f-5)=0 are f=-2/3 ,f=5

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solve for

f, (3 f + 2) (f - 5) = 0

f = - \frac{2}{3}, f = 5

Decimal Notation

f = - 0.66666 \dots, f = 5

Solution steps

(3 f + 2) (f - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 f + 2 = 0 or f - 5 = 0

Solve

3 f + 2 = 0 : f = - \frac{2}{3}

Solve

f - 5 = 0 : f = 5

The solutions to the quadratic equation are:

f = - \frac{2}{3}, f = 5

b, 4 b + 5 = 1 + 5 b

p, p = 4500000 (\frac{( 1 ( 0.02 ) )}{5})^{25}

x, - 7 x = - 56

y = m x + b, 2 y - 3 x = 6

x, - 9 x = 36

What are the solutions to the equation solvefor f,(3f+2)(f-5)=0 ?
The solutions to the equation solvefor f,(3f+2)(f-5)=0 are f=-2/3 ,f=5
Find the zeros of solvefor f,(3f+2)(f-5)=0
The zeros of solvefor f,(3f+2)(f-5)=0 are f=-2/3 ,f=5