What are the solutions to the equation quadraticformula x^2-5x=6 ?

The solutions to the equation quadraticformula x^2-5x=6 are x=6,x=-1

Find the zeros of quadraticformula x^2-5x=6

The zeros of quadraticformula x^2-5x=6 are x=6,x=-1

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x^{2} - 5 x = 6

x = 6, x = - 1

Solution steps

x^{2} - 5 x = 6

Move

6

to the left side

x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

x = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

x = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 6, x = - 1

r, 167 < 6 + 7 (2 - 7 r)

\frac{128}{180}

x, x^{2} = - 4

f, c = \frac{( 5 ( f - 32 ) )}{9}

cos (x^{2})

What are the solutions to the equation quadraticformula x^2-5x=6 ?
The solutions to the equation quadraticformula x^2-5x=6 are x=6,x=-1
Find the zeros of quadraticformula x^2-5x=6
The zeros of quadraticformula x^2-5x=6 are x=6,x=-1