What are the solutions to the equation quadraticformula x^2+6x=7 ?

The solutions to the equation quadraticformula x^2+6x=7 are x=1,x=-7

Find the zeros of quadraticformula x^2+6x=7

The zeros of quadraticformula x^2+6x=7 are x=1,x=-7

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x^{2} + 6 x = 7

x = 1, x = - 7

Solution steps

x^{2} + 6 x = 7

Move

7

to the left side

x^{2} + 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 7) = 8

x_{1, 2} = \frac{- 6 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 8}{2 \cdot 1}, x_{2} = \frac{- 6 - 8}{2 \cdot 1}

x = \frac{- 6 + 8}{2 \cdot 1} : 1

x = \frac{- 6 - 8}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

\frac{66}{20}

x, 1 6^{x - 1} = 8^{x}

x, - 2.6 x + 5 = 3

t, 4 t - 3 > 37 t - 50

x^{2} - 4 x = - 2

What are the solutions to the equation quadraticformula x^2+6x=7 ?
The solutions to the equation quadraticformula x^2+6x=7 are x=1,x=-7
Find the zeros of quadraticformula x^2+6x=7
The zeros of quadraticformula x^2+6x=7 are x=1,x=-7