What are the solutions to the equation quadraticformula 3x^2=6x-3 ?

The solutions to the equation quadraticformula 3x^2=6x-3 are x=1

Find the zeros of quadraticformula 3x^2=6x-3

The zeros of quadraticformula 3x^2=6x-3 are x=1

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3 x^{2} = 6 x - 3

x = 1

Solution steps

3 x^{2} = 6 x - 3

Move

3

to the left side

3 x^{2} + 3 = 6 x

Move

6 x

to the left side

3 x^{2} + 3 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 3 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 3}

x = \frac{- ( - 6 )}{2 \cdot 3}

\frac{- ( - 6 )}{2 \cdot 3} = 1

x = 1

The solution to the quadratic equation is:

x = 1

3 x^{2} + x - 5 = 0

\frac{15}{42}

x, - 8.5 = \frac{x}{2.5 - 3}

\frac{1}{3} \cdot (1800)

y = m x + b, x - y = - 15

What are the solutions to the equation quadraticformula 3x^2=6x-3 ?
The solutions to the equation quadraticformula 3x^2=6x-3 are x=1
Find the zeros of quadraticformula 3x^2=6x-3
The zeros of quadraticformula 3x^2=6x-3 are x=1