What are the solutions to the equation completesquare x^2-12x+27=0 ?

The solutions to the equation completesquare x^2-12x+27=0 are x=9,x=3

Find the zeros of completesquare x^2-12x+27=0

The zeros of completesquare x^2-12x+27=0 are x=9,x=3

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x^{2} - 12 x + 27 = 0

x = 9, x = 3

Solution steps

x^{2} - 12 x + 27 = 0

Move

27

to the right side

x^{2} - 12 x = - 27

Rewrite in the form

(x + a)^{2} = b

(x - 6)^{2} = 9

For

the solutions are

f (x) = a, - a

Solve

x - 6 = 9 : x = 9

Solve

x - 6 = - 9 : x = 3

The solutions to the quadratic equation are:

x = 9, x = 3

40 x^{2}

\frac{( 2 x ^{4} y ^{- 4} z ^{- 3} )}{( 3 x ^{2} y ^{- 3} z ^{4} )}

x, \frac{7}{12} x = \frac{3}{14}

\frac{( sin ( x ) )}{( csc ( x ) )}

x, ∣ x - 6 ∣ = 8

What are the solutions to the equation completesquare x^2-12x+27=0 ?
The solutions to the equation completesquare x^2-12x+27=0 are x=9,x=3
Find the zeros of completesquare x^2-12x+27=0
The zeros of completesquare x^2-12x+27=0 are x=9,x=3