What are the solutions to the equation quadraticformula x^2-2x-5=0 ?

The solutions to the equation quadraticformula x^2-2x-5=0 are x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of quadraticformula x^2-2x-5=0

The zeros of quadraticformula x^2-2x-5=0 are x=1+sqrt(6),x=1-sqrt(6)

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x^{2} - 2 x - 5 = 0

x = 1 + 6, x = 1 - 6

Solution steps

x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 5) = 26

x_{1, 2} = \frac{- ( - 2 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 6}{2 \cdot 1} : 1 + 6

x = \frac{- ( - 2 ) - 2 6}{2 \cdot 1} : 1 - 6

The solutions to the quadratic equation are:

x = 1 + 6, x = 1 - 6

x, \frac{2}{x} = \frac{2}{5}

\frac{13}{5}

(- 10 x)^{2}

x, x + 7 = x - 5

c, c = - 9 - 8 c

What are the solutions to the equation quadraticformula x^2-2x-5=0 ?
The solutions to the equation quadraticformula x^2-2x-5=0 are x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of quadraticformula x^2-2x-5=0
The zeros of quadraticformula x^2-2x-5=0 are x=1+sqrt(6),x=1-sqrt(6)