What are the solutions to the equation 10x^2-2x-3=0 ?

The solutions to the equation 10x^2-2x-3=0 are x=(1+sqrt(31))/(10),x=(1-sqrt(31))/(10)

Find the zeros of 10x^2-2x-3=0

The zeros of 10x^2-2x-3=0 are x=(1+sqrt(31))/(10),x=(1-sqrt(31))/(10)

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10 x^{2} - 2 x - 3 = 0

x = \frac{1 + 31}{10}, x = \frac{1 - 31}{10}

Decimal Notation

x = 0.65677 \dots, x = - 0.45677 \dots

Solution steps

10 x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 10 ( - 3 )}{2 \cdot 10}

(- 2)^{2} - 4 \cdot 10 (- 3) = 231

x_{1, 2} = \frac{- ( - 2 ) \pm 2 31}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 31}{2 \cdot 10}, x_{2} = \frac{- ( - 2 ) - 2 31}{2 \cdot 10}

x = \frac{- ( - 2 ) + 2 31}{2 \cdot 10} : \frac{1 + 31}{10}

x = \frac{- ( - 2 ) - 2 31}{2 \cdot 10} : \frac{1 - 31}{10}

The solutions to the quadratic equation are:

x = \frac{1 + 31}{10}, x = \frac{1 - 31}{10}

2 x + 1 = 6

x^{2} - 6 x - 27 < 0

82 \cdot 2

lo g_{3} (0.5)

\frac{( x + 8 )}{4} + \frac{( x - 2 )}{3} = (\frac{23}{12})

What are the solutions to the equation 10x^2-2x-3=0 ?
The solutions to the equation 10x^2-2x-3=0 are x=(1+sqrt(31))/(10),x=(1-sqrt(31))/(10)
Find the zeros of 10x^2-2x-3=0
The zeros of 10x^2-2x-3=0 are x=(1+sqrt(31))/(10),x=(1-sqrt(31))/(10)