What are the solutions to the equation quadraticformula x^2=4x-4 ?

The solutions to the equation quadraticformula x^2=4x-4 are x=2

Find the zeros of quadraticformula x^2=4x-4

The zeros of quadraticformula x^2=4x-4 are x=2

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x^{2} = 4 x - 4

x = 2

Solution steps

x^{2} = 4 x - 4

Move

4

to the left side

x^{2} + 4 = 4 x

Move

4 x

to the left side

x^{2} + 4 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

2 x^{2} - x - 2 = 0

k, 3 k - 1 = 7 k + 2

1/2.5/4

c, 5 c + 16.5 = 13.5 + 10 c

5.34%

What are the solutions to the equation quadraticformula x^2=4x-4 ?
The solutions to the equation quadraticformula x^2=4x-4 are x=2
Find the zeros of quadraticformula x^2=4x-4
The zeros of quadraticformula x^2=4x-4 are x=2