What are the solutions to the equation quadraticformula 4x^2-5x+1=0 ?

The solutions to the equation quadraticformula 4x^2-5x+1=0 are x=1,x= 1/4

Find the zeros of quadraticformula 4x^2-5x+1=0

The zeros of quadraticformula 4x^2-5x+1=0 are x=1,x= 1/4

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4 x^{2} - 5 x + 1 = 0

x = 1, x = \frac{1}{4}

Decimal Notation

x = 1, x = 0.25

Solution steps

4 x^{2} - 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 \cdot 1 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 4}

x = \frac{- ( - 5 ) + 3}{2 \cdot 4} : 1

x = \frac{- ( - 5 ) - 3}{2 \cdot 4} : \frac{1}{4}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{4}

n, 4 n - 2 n = 4

y, - 8 (y + 9) = - 40

\frac{45}{125}

6 x^{2} - 11 x - 10 = 0

(1.06)^{25}

What are the solutions to the equation quadraticformula 4x^2-5x+1=0 ?
The solutions to the equation quadraticformula 4x^2-5x+1=0 are x=1,x= 1/4
Find the zeros of quadraticformula 4x^2-5x+1=0
The zeros of quadraticformula 4x^2-5x+1=0 are x=1,x= 1/4