What is expand (ln(3x^2))/e ?

The solution to expand (ln(3x^2))/e is (ln(3))/e+(2ln(x))/e

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Expand the Logarithmic Expression natural log of (3x^2)/e

expand

\frac{ln ( 3 x ^{2} )}{e}

\frac{ln ( 3 )}{e} + \frac{2 ln ( x )}{e}

Solution steps

\frac{ln ( 3 x ^{2} )}{e}

Simplify

ln (3 x^{2}) : 2 ln (x) + ln (3)

= \frac{ln ( 3 ) + 2 ln ( x )}{e}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{ln ( 3 ) + 2 ln ( x )}{e} = \frac{ln ( 3 )}{e} + \frac{2 ln ( x )}{e}

= \frac{ln ( 3 )}{e} + \frac{2 ln ( x )}{e}

\frac{( - 100 )}{( - 5 )}

\frac{( cos ^{2} ( \frac{π}{2 - x} ) )}{( 1 - sin ^{2} ( x ) )}

\frac{( - 81 )}{( - 3 )}

x, ∣ x ∣ = 0

\frac{( 126 )}{( 7 )}

What is expand (ln(3x^2))/e ?
The solution to expand (ln(3x^2))/e is (ln(3))/e+(2ln(x))/e