What is the answer to 4|x-12|+1=-7|x-12|+1 ?

The answer to 4|x-12|+1=-7|x-12|+1 is x=12

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4|x-12|+1=-7|x-12|+1

4 ∣ x - 12 ∣ + 1 = - 7 ∣ x - 12 ∣ + 1

x = 12

Solution steps

4 ∣ x - 12 ∣ + 1 = - 7 ∣ x - 12 ∣ + 1

Subtract

1

from both sides

4 ∣ x - 12 ∣ + 1 - 1 = - 7 ∣ x - 12 ∣ + 1 - 1

Simplify

4 ∣ x - 12 ∣ = - 7 ∣ x - 12 ∣

Move

7 ∣ x - 12 ∣

to the left side

11 ∣ x - 12 ∣ = 0

Divide both sides by

11

∣ x - 12 ∣ = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

x - 12 = 0

x - 12 = 0 : x = 12

x = 12

∣ 3 x - 1 ∣ \leq - 5

(\frac{25}{36})^{\frac{1}{2}}

(x + 2)^{2} - 10 (x + 2) = - 9

\frac{1}{2} (2) - 1

(10)^{- 2}

What is the answer to 4|x-12|+1=-7|x-12|+1 ?
The answer to 4|x-12|+1=-7|x-12|+1 is x=12
Solve for x: 4|x-12|+1=-7|x-12|+1
The solution is x=12