What are the solutions to the equation 89x^2+1=16x ?

The solutions to the equation 89x^2+1=16x are x= 8/89+i 5/89 ,x= 8/89-i 5/89

Find the zeros of 89x^2+1=16x

The zeros of 89x^2+1=16x are x= 8/89+i 5/89 ,x= 8/89-i 5/89

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89 x^{2} + 1 = 16 x

x = \frac{8}{89} + i \frac{5}{89}, x = \frac{8}{89} - i \frac{5}{89}

Solution steps

89 x^{2} + 1 = 16 x

Move

16 x

to the left side

89 x^{2} + 1 - 16 x = 0

Write in the standard form

a x^{2} + b x + c = 0

89 x^{2} - 16 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 89 \cdot 1}{2 \cdot 89}

Simplify

(- 16)^{2} - 4 \cdot 89 \cdot 1 : 10 i

x_{1, 2} = \frac{- ( - 16 ) \pm 10 i}{2 \cdot 89}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 10 i}{2 \cdot 89}, x_{2} = \frac{- ( - 16 ) - 10 i}{2 \cdot 89}

x = \frac{- ( - 16 ) + 10 i}{2 \cdot 89} : \frac{8}{89} + i \frac{5}{89}

x = \frac{- ( - 16 ) - 10 i}{2 \cdot 89} : \frac{8}{89} - i \frac{5}{89}

The solutions to the quadratic equation are:

x = \frac{8}{89} + i \frac{5}{89}, x = \frac{8}{89} - i \frac{5}{89}

2 n^{2} - 24 n + 72

2 x^{2} - x - 10 = 0

(- \frac{1}{x})^{2}

∣ 2 x - 7 ∣ = ∣ 3 x - 9 ∣

7 (x - 1) \geq 3 x + 2

What are the solutions to the equation 89x^2+1=16x ?
The solutions to the equation 89x^2+1=16x are x= 8/89+i 5/89 ,x= 8/89-i 5/89
Find the zeros of 89x^2+1=16x
The zeros of 89x^2+1=16x are x= 8/89+i 5/89 ,x= 8/89-i 5/89