What are the solutions to the equation (x-4)^2=-9 ?

The solutions to the equation (x-4)^2=-9 are x=3i+4,x=-3i+4

Find the zeros of (x-4)^2=-9

The zeros of (x-4)^2=-9 are x=3i+4,x=-3i+4

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(x - 4)^{2} = - 9

x = 3 i + 4, x = - 3 i + 4

Solution steps

(x - 4)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = - 9 : x = 3 i + 4

Solve

x - 4 = - - 9 : x = - 3 i + 4

The solutions to the quadratic equation are:

x = 3 i + 4, x = - 3 i + 4

\frac{( x + 2 ) ^{2}}{5} - \frac{x ^{2} - 9}{4} = \frac{( x + 3 ) ^{2}}{2} + \frac{1}{5}

x^{2} - 9 x y - 36 y^{2}

4 x^{2} - 12 x + 9 = 0

8 m^{2} - 6 m - 5

\frac{( a - b ) ^{2}}{b - a}

What are the solutions to the equation (x-4)^2=-9 ?
The solutions to the equation (x-4)^2=-9 are x=3i+4,x=-3i+4
Find the zeros of (x-4)^2=-9
The zeros of (x-4)^2=-9 are x=3i+4,x=-3i+4