What are the solutions to the equation t(320-32t)=0 ?

The solutions to the equation t(320-32t)=0 are t=0,t=10

Find the zeros of t(320-32t)=0

The zeros of t(320-32t)=0 are t=0,t=10

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t (320 - 32 t) = 0

t = 0, t = 10

Solution steps

t (320 - 32 t) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t = 0 or 320 - 32 t = 0

Solve

320 - 32 t = 0 : t = 10

The solutions to the quadratic equation are:

t = 0, t = 10

x + 2 y + x + 2

\frac{4 x - 3}{4} - \frac{3 x - 1}{2} > 1

x^{4} + 12 x^{2} + 35

- 6 \leq - 2 k + 4 \leq 2

\frac{2 x + 3}{x ^{2} + 2 x - 15} \geq 0

What are the solutions to the equation t(320-32t)=0 ?
The solutions to the equation t(320-32t)=0 are t=0,t=10
Find the zeros of t(320-32t)=0
The zeros of t(320-32t)=0 are t=0,t=10