What is 13-2|x+4|>5 ?

The solution to 13-2|x+4|>5 is -8<x<0

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13-2|x+4|>5

13 - 2 ∣ x + 4 ∣ > 5

- 8 < x < 0

Interval Notation

(- 8, 0)

Solution steps

13 - 2 ∣ x + 4 ∣ > 5

Move

13

to the right side

- 2 ∣ x + 4 ∣ > - 8

Multiply both sides by

- 1

2 ∣ x + 4 ∣ < 8

Divide both sides by

2

∣ x + 4 ∣ < 4

Apply absolute rule: If

∣ u ∣ < a, a > 0

then

- a < u < a

- 4 < x + 4 < 4

x + 4 > - 4 and x + 4 < 4

x > - 8 and x < 0

Merge Overlapping Intervals

- 8 < x < 0

\frac{12.01}{98.182} \cdot 100%

x (x + 8) = - 20

x^{2} - 11 = 10 x

(3 x^{2} y^{3})^{3}

6 x^{2} - 3 x + 2 = 0