What are the solutions to the equation 2x^2-17x+35=0 ?

The solutions to the equation 2x^2-17x+35=0 are x=5,x= 7/2

Find the zeros of 2x^2-17x+35=0

The zeros of 2x^2-17x+35=0 are x=5,x= 7/2

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2 x^{2} - 17 x + 35 = 0

x = 5, x = \frac{7}{2}

Decimal Notation

x = 5, x = 3.5

Solution steps

2 x^{2} - 17 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 2 \cdot 35}{2 \cdot 2}

(- 17)^{2} - 4 \cdot 2 \cdot 35 = 3

x_{1, 2} = \frac{- ( - 17 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 17 ) - 3}{2 \cdot 2}

x = \frac{- ( - 17 ) + 3}{2 \cdot 2} : 5

x = \frac{- ( - 17 ) - 3}{2 \cdot 2} : \frac{7}{2}

The solutions to the quadratic equation are:

x = 5, x = \frac{7}{2}

x^{2} - 6 x + 16 > 0

4 x - 2 (x + 1) > 3 - 3 (x + 2)

- 18 x + 21 > - 15

\frac{3 + \frac{3}{a}}{\frac{3}{a}}

x = 131 \frac{3333 + ( 1000 )}{3333 - ( 1000 )}

What are the solutions to the equation 2x^2-17x+35=0 ?
The solutions to the equation 2x^2-17x+35=0 are x=5,x= 7/2
Find the zeros of 2x^2-17x+35=0
The zeros of 2x^2-17x+35=0 are x=5,x= 7/2