What are the solutions to the equation s^2+2s+4=0 ?

The solutions to the equation s^2+2s+4=0 are s=-1+sqrt(3)i,s=-1-sqrt(3)i

Find the zeros of s^2+2s+4=0

The zeros of s^2+2s+4=0 are s=-1+sqrt(3)i,s=-1-sqrt(3)i

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s^{2} + 2 s + 4 = 0

s = - 1 + 3 i, s = - 1 - 3 i

Solution steps

s^{2} + 2 s + 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 4 : 23 i

s_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 2 3 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 2 3 i}{2 \cdot 1}

s = \frac{- 2 + 2 3 i}{2 \cdot 1} : - 1 + 3 i

s = \frac{- 2 - 2 3 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

s = - 1 + 3 i, s = - 1 - 3 i

- 8 x^{2} - 15 x + 2

(4 + 3 i) (2 - 5 i)

s^{2} - 36

\frac{12}{\frac{3}{4}}

\frac{1}{10} - \frac{1}{6} + \frac{1}{14}

What are the solutions to the equation s^2+2s+4=0 ?
The solutions to the equation s^2+2s+4=0 are s=-1+sqrt(3)i,s=-1-sqrt(3)i
Find the zeros of s^2+2s+4=0
The zeros of s^2+2s+4=0 are s=-1+sqrt(3)i,s=-1-sqrt(3)i